You measure out 3.00 mL of 0.100 M Co(NO3)2, place it in a test tube and add 7.00 mL of water. What is the concentration of the diluted solution in the test tube?
0.03
10/3 the volume, 3/10 the concentration.
0.1 M x (3 mL/10 mL) = ?
To find the concentration of the diluted solution, we can use the dilution formula:
C1V1 = C2V2
Where:
C1 = initial concentration of the solution
V1 = initial volume of the solution
C2 = final concentration of the solution
V2 = final volume of the solution
In this case, we have:
C1 = 0.100 M (concentration of the initial solution)
V1 = 3.00 mL (volume of the initial solution)
C2 = ? (final concentration of the solution, what we want to find)
V2 = 3.00 mL + 7.00 mL = 10.00 mL (volume of the final solution)
Now, let's substitute the given values into the dilution formula:
(0.100 M)(3.00 mL) = C2(10.00 mL)
Solving for C2:
(0.100 M)(3.00 mL) / (10.00 mL) = C2
This equation simplifies to:
C2 = 0.030 M
Therefore, the concentration of the diluted solution in the test tube is 0.030 M.