The combined resistance of two identical resistors connected in series is 8 ohm. Their combined resistance in a parallel arrangement will be?
2 ohms....
2 ohms
how it will be 2 ohm
How will it 2 ohm plzz tell me
2ohm
i know it will 2 ohm but why
To find the combined resistance of two identical resistors in a series arrangement, we add the individual resistances together. Since the combined resistance is given as 8 ohms, it means that the resistance of each resistor is 4 ohms (8 ohms divided by 2).
Now, let's calculate the combined resistance of the two resistors in a parallel arrangement.
In a parallel circuit, the combined resistance (Rp) can be calculated using the formula:
1/Rp = 1/R1 + 1/R2 + ...
Where R1 and R2 are the resistances of the individual resistors.
Since the two resistors are identical, their resistance is the same, let's call it R. Therefore, the formula becomes:
1/Rp = 1/R + 1/R
Simplifying further:
1/Rp = 2/R
To eliminate the fraction, we can cross-multiply:
R × 1/Rp = 2
Simplifying again:
R/Rp = 2
Finally, rearranging the equation to solve for Rp:
Rp = R/2
Since we know the resistance of each individual resistor is 4 ohms, we can substitute R = 4 into the equation:
Rp = 4/2
Rp = 2 ohms
Therefore, the combined resistance of two identical resistors connected in a parallel arrangement will be 2 ohms.