Suppose a student diluted and titrated a bleach unknown exactly as described in the experimental procedure, except only a single titration was performed which required 16.22 mL of 0.100 M Na2S2O3.
Calculate the number of moles of Na2S2O3 used in the titration.
(16.22mL) * (1L/1000mL) * (0.100 moles/L) = ? moles
How would I calculate the number of moles in CIO- from the sample titrated also?
To calculate the number of moles of Na2S2O3 used in the titration, we need to use the volume and concentration of Na2S2O3 solution.
Given:
- Volume of Na2S2O3 solution used in the titration: 16.22 mL
- Concentration of Na2S2O3 solution: 0.100 M
To calculate the number of moles of Na2S2O3, we can use the formula:
moles = volume × concentration
First, we need to convert the volume from milliliters to liters:
16.22 mL ÷ 1000 = 0.01622 L
Now we can substitute the values into the formula:
moles = 0.01622 L × 0.100 M
moles = 0.001622 mol
Therefore, the number of moles of Na2S2O3 used in the titration is 0.001622 mol.