A person has R200,000 invested, part at 9% and part at 8%. If the total yearly income from the two investments is R17200, how much is invested at 9% and how much at 8%?
part at 9% -- x
part at 8% -- 200,000 -x
.09x + .08(200000-x) = 17200
take over
Good one but need a step
Let's assume that the amount invested at 9% is x, and the amount invested at 8% is (R200,000 - x).
The yearly income from the 9% investment can be calculated by multiplying the amount invested at 9% (x) by the interest rate (9%) and then dividing by 100.
The yearly income from the 8% investment can be calculated by multiplying the amount invested at 8% (R200,000 - x) by the interest rate (8%) and then dividing by 100.
We can set up the equation:
(x * 9/100) + ((R200,000 - x) * 8/100) = R17,200
Now, let's solve for x:
(9x/100) + (8(R200,000 - x)/100) = R17,200
(9x/100) + (1600,000 - 8x)/100 = R17,200
(9x + 1600,000 - 8x) / 100 = R17,200
Combine like terms:
x + 1600,000 = 17,200 * 100
x + 1600,000 = 1,720,000
x = 1,720,000 - 1600,000
x = R120,000
Therefore, R120,000 is invested at 9% and R200,000 - R120,000 = R80,000 is invested at 8%.
To solve this problem, let's assume that the amount invested at 9% is x, and the amount invested at 8% is (R200,000 - x).
First, we need to calculate the income earned from the investment at 9%. The formula for calculating income is as follows:
Income = Principal * Rate
Therefore, the income earned from the investment at 9% would be (x * 0.09).
Next, we calculate the income earned from the investment at 8%, using the same formula:
Income = Principal * Rate
Therefore, the income earned from the investment at 8% would be ((R200,000 - x) * 0.08).
Now, we can set up an equation to represent the total yearly income:
(x * 0.09) + ((R200,000 - x) * 0.08) = R17,200
To solve this equation, we can distribute and simplify:
0.09x + (0.08 * R200,000) - (0.08x) = R17,200
0.09x - 0.08x + 0.08 * R200,000 = R17,200
0.01x + 0.08 * R200,000 = R17,200
0.01x = R17,200 - 0.08 * R200,000
0.01x = R17,200 - R16,000
0.01x = R1,200
x = R1,200 / 0.01
x = R120,000
Therefore, R120,000 is invested at 9% and (R200,000 - R120,000) = R80,000 is invested at 8%.