Two wires are identical, except that one is aluminum and one is copper. The aluminum wire has a resistance of 0.527Ω. What is the resistance of the copper wire? Take the resistivity of copper to be 1.72 x 10-8 Ω·m, and that of aluminum to be 2.82 x 10-8 Ω·m.

R = (1.72*10^-80/2.82*10^-8) * 0.527 Ohms = 0.321 Ohms.

To find the resistance of the copper wire, we can use the formula:

Resistance = Resistivity x Length / Cross-sectional Area

Since the wires are identical, we can assume they have the same length and cross-sectional area. Therefore, the ratio of their resistivities will be equal to the ratio of their resistances.

Resistivity of copper (ρ_copper) = 1.72 x 10^-8 Ω·m
Resistivity of aluminum (ρ_aluminum) = 2.82 x 10^-8 Ω·m
Resistance of aluminum wire (R_aluminum) = 0.527 Ω

Now, we can set up a proportion to find the resistance of the copper wire (R_copper):

(R_copper) / (R_aluminum) = (ρ_copper) / (ρ_aluminum)

R_copper / 0.527 Ω = 1.72 x 10^-8 Ω·m / 2.82 x 10^-8 Ω·m

R_copper = (0.527 Ω) x (1.72 x 10^-8 Ω·m) / (2.82 x 10^-8 Ω·m)

R_copper = 0.321 Ω

Therefore, the resistance of the copper wire is 0.321 Ω.

To find the resistance of the copper wire, we can use the formula for resistance:

R = (ρ * L) / A

where R is the resistance, ρ (rho) is the resistivity of the material, L is the length of the wire, and A is the cross-sectional area.

We know the resistivity of copper (ρ) is 1.72 x 10-8 Ω·m, and the resistivity of aluminum (ρ) is 2.82 x 10-8 Ω·m. However, we do not have the length or cross-sectional area of the wires.

The given information states that the wires are identical, except for their resistances. This suggests that the wires have the same length and cross-sectional area. Therefore, we can assume that the length (L) and cross-sectional area (A) of both wires are the same.

Let's denote the resistance of the aluminum wire as R_aluminum = 0.527 Ω.

Using the formula for resistance, we can rewrite it as:

R_aluminum = (ρ_aluminum * L) / A

Since we assume that the length and cross-sectional area are the same for both wires, we can rewrite the equation as:

R_copper = (ρ_copper * L) / A

Given that ρ_aluminum = 2.82 x 10-8 Ω·m, R_aluminum = 0.527 Ω, and ρ_copper = 1.72 x 10-8 Ω·m, we can plug in these values to solve for R_copper:

0.527 Ω = (1.72 x 10-8 Ω·m * L) / A

To find the resistance of the copper wire, we rearrange the equation:

R_copper = (0.527 Ω * A) / (1.72 x 10-8 Ω·m)

Now, we need the cross-sectional area (A) of the wire. Unfortunately, this information is not provided in the question. Without the cross-sectional area, we cannot find the resistance of the copper wire without additional information.