A car moving with a speed of 180kmh was brought uniformly to rest by the application of the breaks in 20s. How far did the car travel after the breaks
Vi = 180,000 meters/3600 seconds
average speed during deacceleration= Vi/2
distance = (Vi/2)* 20 = 10 Vi
To find the distance traveled by the car after the brakes were applied, we need to use the equation:
distance = initial speed * time + (1/2) * acceleration * time^2
In this case, the initial speed of the car is 180 km/h, which needs to be converted to m/s. We can do this by multiplying it by (1000/3600):
180 km/h * (1000/3600) = 50 m/s
The time taken to bring the car to rest is 20 seconds. Since the car came to rest, the final speed is 0 m/s.
The equation then becomes:
distance = 50 m/s * 20 s + (1/2) * 0 * (20 s)^2
Simplifying this equation, the second term (1/2) * 0 * (20 s)^2 becomes 0, which leaves us with:
distance = 50 m/s * 20 s = 1000 meters
Therefore, the car traveled a distance of 1000 meters after the brakes were applied.