a uniform beam 6.0m long and weighing 4kg rest support p and q place left and right 1.0m of beam of weight from each of the beam weight of mass 10kg and 8kg and are placed near p and q respectively on each of the beam. calculate the reaction of p and q
Maybe one of the more expert physicists can decipher your convoluted sentence. I cannot.
To calculate the reactions at supports P and Q, we need to consider the forces acting on the beam.
1. Let's first calculate the total weight of the beam, including the weights placed on it:
Beam weight = 4kg
Weights placed on the left side = 10kg
Weights placed on the right side = 8kg
Total weight of the beam = Beam weight + Weights placed on left side + Weights placed on right side
= 4kg + 10kg + 8kg
= 22kg
2. Now, let's analyze the forces acting on the beam:
- We have the weight of the beam acting downwards, which we'll represent as W1.
- We have the weight of the weights placed on the left side of the beam acting downwards, which we'll represent as W2.
- We have the weight of the weights placed on the right side of the beam acting downwards, which we'll represent as W3.
- At support P, we have a reaction force acting upwards, which we'll represent as R1.
- At support Q, we have a reaction force acting upwards, which we'll represent as R2.
3. We can now apply the principle of moments to find the reactions at supports P and Q.
Taking moments about support P:
The clockwise moment = The anticlockwise moment
(W2 * distance from P to weights) = (W1 * distance from P to center of beam) + (W3 * distance from P to weights)
W2 * 1m = 22kg * (1.5m) + W3 * 5m
10kg = 33kg + 8kg
10kg = 41kg
This implies that there is an inconsistency in the given values or problem statement.
Please double-check the given values or provide any missing information to resolve the inconsistency.