A sixth number will be added to the list. What must it be in order for the mean to be 12? (Use algebraic equation to help)

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16 :)

A sixth number will be added to the list. What must it be in order for the mean to be 12???

Mean= adding all the numbers together and then dividing that by how many numbers there are.
7,16,11,12,10,___

7,16,11,12,10

how did you get 16 as the answer

I think you have a typo.

You want a 6th added, so there should have been 5 of them given already. You only have four of them

The list is 7,16,12,10

To find the sixth number that must be added to the list in order for the mean to be 12, we need to understand the concept of mean and use an algebraic equation.

The mean of a list of numbers is found by summing all the numbers in the list and dividing by the total count of numbers. Let's assume the original list has n numbers and their sum is S (the sum of the list).

Let's represent the sixth number as x. So, we have a new list with n+1 numbers, where the sum of the new list is S + x (the sum of the original list plus the new number).

To find the mean of the new list, we divide the sum (S + x) by the total count of numbers (n + 1):

Mean = (S + x) / (n + 1)

We want the mean to be 12, so we set up the equation:

12 = (S + x) / (n + 1)

Now we can solve for x. We'll rearrange the equation to isolate x:

12(n + 1) = S + x

12n + 12 = S + x

x = 12n + 12 - S

Therefore, the sixth number (x) that must be added to the list in order for the mean to be 12 is given by the expression 12n + 12 - S.

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