Can you please confirm that my answer is correct to this problem?
80x2^ - 96x + 27 =0
I am using the quadratic formula to solve... I would put the formula here but I can't put the square root sign in here.
My answer is -1.33 and -2.22
Is this correct? thank you
well, did you try the values, to see whether they work?
80*(-1.33)^2 - 96(-1.33) + 27 = 296.192
Hmmm. I'd say nope.
So, too bad you didn't show your work...
80x2^ - 96x + 27 =0
Using the quadratic formula, since there are so many possible factors of 80 and 27,
x = (96±√(96^2-4*80*27)]/160
= (96±√576)/160
= (96±24)/160
= 120/160 or 72/160
= 3/4 or 9/20
so, the factorization must be
(4x-3)(20x-9) = 0
To confirm if your answer is correct, we first need to properly format and solve the quadratic equation:
80x^2 - 96x + 27 = 0
To use the quadratic formula, recall that it is given by:
x = (-b ± √(b^2 - 4ac)) / (2a)
In this case, a = 80, b = -96, and c = 27. Now we can substitute these values into the formula:
x = (-(-96) ± √((-96)^2 - 4(80)(27))) / (2(80))
Simplifying further:
x = (96 ± √(9216 - 8640)) / 160
x = (96 ± √576) / 160
x = (96 ± 24) / 160
Now, let's consider both possibilities:
x = (96 + 24) / 160 = 120 / 160 = 0.75
x = (96 - 24) / 160 = 72 / 160 = 0.45
So, it seems the correct solutions to the quadratic equation are x = 0.75 and x = 0.45.
Hence, your answer of -1.33 and -2.22 is incorrect.