system of linear equations of substitution.
a=2/b-3
a=2b-8
a = 2b-8, so (assuming the usual sloppiness with parentheses)
2b-8 = 2/(b-3)
(b-4)(b-3) = 1
Now just solve the quadratic. I suspect a typo, just fyi.
a=2/b-3
a=2b-8
2b-8 = 2/(b-3)
(b-4)(b-3) = 1
Now just solve the quadratic. I suspect a typo, just fyi.