how many chloride ions are in 0.28 mol MgCl2?

.28 * 6.023 * 10^23 * 2

To determine the number of chloride ions in 0.28 mol of MgCl2, you need to consider the ratio of chloride ions to magnesium chloride molecules.

In MgCl2, there are two chloride ions for every one magnesium chloride molecule. This means that for every mole of MgCl2, there are two moles of chloride ions.

So, to find the number of moles of chloride ions in 0.28 mol of MgCl2, we can simply multiply 0.28 mol by 2.

Number of moles of chloride ions = 0.28 mol * 2 = 0.56 mol

Since there are 6.022 x 10^23 particles in one mole of a substance (Avogadro's number), we can calculate the number of chloride ions using the following equation:

Number of chloride ions = Number of moles of chloride ions * Avogadro's number

Number of chloride ions = 0.56 mol * 6.022 x 10^23 molecules/mol

After performing the calculation, you will find that there are approximately 3.373 x 10^23 chloride ions in 0.28 mol of MgCl2.