a heterozygous tall pea plant is crossed with a short pea plant.what are the expected genotypic and phenotypic ratio for this cross
what is the answer to it
Assuming tall is dominant and short is recessive, use Ts and ss in a Punnett Square.
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In roses, long stem is dominant over short stems. A Homozygous long-stemmed plant is crossed with a homozygous short-stemmed plant. What percentage of the resultant rose plants
will have long stems?
To determine the expected genotypic and phenotypic ratios for a cross between a heterozygous tall (Tt) pea plant and a short (tt) pea plant, we need to consider the possible combinations of alleles in the offspring.
In this case, the genotype of the heterozygous tall plant (Tt) means that it carries one allele for tallness (T) and one allele for shortness (t). The genotype of the short plant (tt) means that it carries two alleles for shortness (t).
When the two plants are crossed, the possible combinations of alleles for the offspring are as follows:
1. Tt (tall)
2. Tt (tall)
3. tt (short)
4. tt (short)
Now, let's determine the genotypic and phenotypic ratios:
Genotypic ratio:
Out of the four possible combinations, two result in the genotype Tt (tall) and two result in the genotype tt (short). Therefore, the genotypic ratio is 2:2, or 1:1.
Phenotypic ratio:
Since the T allele is dominant over the t allele, both Tt and TT genotypes will exhibit the tall phenotype. Only the tt genotype will show the short phenotype. Therefore, the phenotypic ratio is as follows:
Tall (Tt) + Tall (Tt): 2 plants
Short (tt): 2 plants
The phenotypic ratio is 2:2, or 1:1.
In summary, the expected genotypic ratio for this cross is 1:1 (Tt:tt), and the expected phenotypic ratio is also 1:1 (Tall:Short).