Which solution set best fit the solutions of -1.5^2+4x+2.2=0
2.2 and 3.1 or this one...
no real solution
-0.5 and 2.2
-0.5 and 3.1 <--
Well, why don't we solve it, probably faster than subbing in all those values
-1.5^2+4x+2.2=0
3x^2 - 8x - 4.4 = 0
x = (8 ± √116.8)/6 = appr 3.13 or -.5
you are right
Thank you
To find the solution set for the given quadratic equation -1.5^2+4x+2.2=0, we need to solve the equation for x.
The given equation is in the form of ax^2 + bx + c = 0, where a = -1.5, b = 4, and c = 2.2.
One way to solve this quadratic equation is by using the quadratic formula:
x = (-b ± √(b^2 - 4ac)) / (2a)
Substituting the values into the formula, we get:
x = (-(4) ± √((4)^2 - 4(-1.5)(2.2))) / (2(-1.5))
Simplifying further, we have:
x = (-4 ± √(16 + 13.2)) / (-3)
x = (-4 ± √(29.2)) / (-3)
Since the discriminant (√(b^2 - 4ac)) is positive, there are two real solutions.
Now we can calculate the solutions:
x = (-4 + √(29.2)) / (-3) ≈ -2.06
x = (-4 - √(29.2)) / (-3) ≈ 0.73
Therefore, the correct solution set is:
x ≈ -2.06 and x ≈ 0.73
So, the option that best fits the solutions is -0.5 and 3.1.