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The particular solution of the differential equation dy/dt equals y over 4 for which y(0) = 20 is

y = 20e−0.25t
y = 19 + e0.25t
y = 20 e0.25t - my answer
y = 20e4t

  • math -

    dy/dt = y/4
    dy/y = 1/44 dt
    lny = t/4 + c
    y = c*e^(t/4)

    y(0)=20, so

    c*e^0 = 10
    c = 20

    y = 20e^(t/4)

    You are correct.

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