# math

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The particular solution of the differential equation dy/dt equals y over 4 for which y(0) = 20 is

y = 20e−0.25t
y = 19 + e0.25t
y = 20 e0.25t - my answer
y = 20e4t

• math -

dy/dt = y/4
dy/y = 1/44 dt
lny = t/4 + c
y = c*e^(t/4)

y(0)=20, so

c*e^0 = 10
c = 20

y = 20e^(t/4)

You are correct.

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