write the net ionic equation (including phases) that corresponds to zn(no3)2 + Na2CO3--->ZnCO3+2NaNO3.
To write the net ionic equation, we need to first write the complete ionic equation and then cancel out the spectator ions. Here are the steps:
Step 1: Write the balanced equation for the reaction:
Zn(NO3)2 + Na2CO3 → ZnCO3 + 2NaNO3
Step 2: Separate the soluble compounds into ions (if applicable):
Zn^2+(aq) + 2NO3^-(aq) + 2Na+(aq) + CO3^2-(aq) → ZnCO3(s) + 2Na+(aq) + 2NO3^-(aq)
Step 3: Cancel out the spectator ions, those ions that appear on both sides unchanged:
Canceling out the 2Na+(aq) and 2NO3^-(aq) ions, the net ionic equation is:
Zn^2+(aq) + CO3^2-(aq) → ZnCO3(s)
Therefore, the net ionic equation for the reaction is:
Zn^2+(aq) + CO3^2-(aq) → ZnCO3(s)
To write the net ionic equation, we need to identify the species that are actually reacting and participating in the chemical reaction. In this case, the reactants are Zn(NO3)2 (zinc nitrate) and Na2CO3 (sodium carbonate), and the products are ZnCO3 (zinc carbonate) and NaNO3 (sodium nitrate).
Before writing the net ionic equation, let's first write the balanced chemical equation for the reaction:
Zn(NO3)2 + Na2CO3 -> ZnCO3 + 2NaNO3
Now, let's break down the equation into its respective ions and determine which ones are soluble and insoluble. The soluble ions are dissociated into their respective ions in the reaction solution, while the insoluble ions stay together as a solid.
The soluble ions in this reaction are:
- Zn(NO3)2: Zn2+ and 2NO3-
The insoluble ions in this reaction are:
- ZnCO3: ZnCO3 (solid)
Now, let's write the complete ionic equation, where the soluble compounds are written as dissociated ions:
Zn2+ (aq) + 2NO3- (aq) + 2Na+ (aq) + CO3^2- (aq) -> ZnCO3 (s) + 2Na+ (aq) + 2NO3- (aq)
Finally, we can cancel out the spectator ions (ions that remain the same on both sides of the equation) to obtain the net ionic equation:
Zn2+ (aq) + CO3^2- (aq) -> ZnCO3 (s)
So, the net ionic equation for the reaction is:
Zn2+ (aq) + CO3^2- (aq) -> ZnCO3 (s)