Make h subject of formula in A=πr√h²-r²
The way you typed it, √h^2 would simply be h
Is that what you want or did you mean:
A=πr√(h²-r²) -----> critical brackets
I will wait for your reply
A=πr√h²+r²
A=πr√h²+r²
DBS by πr
A/πr =√h²+r²
√A/πr = √h²+r²
√A/πr = h²+r²
√A/πr - r² = h²
√A²/πr² - r² = h
h=√A²/πr² - r² ans..
i want an answer!!!!!
Pls I need the answer and how to work it
A=πr√(h²+r²)
To make "h" the subject of the formula A = πr√h² - r², we need to isolate "h" on one side of the equation. Here's how we can do that step by step:
1. Start with the formula: A = πr√h² - r².
2. Add r² to both sides of the equation to remove it from the right side:
A + r² = πr√h².
3. Divide both sides of the equation by πr to isolate the square root term:
(A + r²) / (πr) = √h².
4. Square both sides of the equation to eliminate the square root:
[(A + r²) / (πr)]² = h².
5. Simplify the right side of the equation:
h² = (A + r²)² / (πr)².
6. Take the square root of both sides to isolate "h":
h = √[(A + r²)² / (πr)²].
Therefore, "h" is the subject of the formula in A = πr√h² - r², expressed as h = √[(A + r²)² / (πr)²].