Express the absolute value of the partial charges as a decimal fraction of the elementary charge for CH. The bond length, is 131.1 pm, and the Dipole Moment, D is 1.46

To calculate the absolute value of the partial charges as a decimal fraction of the elementary charge (e), you can use the following equation:

|q| = (D * √(4πε₀) / (e * r)

where:
|q| is the absolute value of the partial charge
D is the dipole moment
ε₀ is the vacuum permittivity (ε₀ = 8.854 x 10⁻¹² C²/Nm²)
e is the elementary charge (e = 1.602 x 10⁻¹⁹ C)
r is the bond length

Let's substitute the given values into the equation:

|q| = (1.46 * √(4π * 8.854 x 10⁻¹²) / (1.602 x 10⁻¹⁹ * 131.1 x 10⁻¹²)

|q| = (1.46 * √(4π * 8.854 x 10⁻¹²) / (1.602 x 10⁻¹⁹ * 1.311 x 10⁻¹⁰)

Calculating this expression will give you the decimal fraction of the elementary charge.

To express the absolute value of the partial charges as a decimal fraction of the elementary charge for CH (methyl radical), you would need to use the bond length and dipole moment provided.

Here's how you can calculate it step by step:

Step 1: Find the charge separation (δ) using the formula: δ = D / (d * e)

Where:
- D is the dipole moment
- d is the bond length
- e is the elementary charge (1.602 x 10^-19 C)

Substituting the given values:
δ = 1.46 / (131.1 x 10^-12 m * 1.602 x 10^-19 C)

Step 2: Evaluate the numerical value of δ.

Let's calculate it:
δ = 1.46 / (2.095722 x 10^-29)

δ ≈ 6.96 x 10^9 C

Step 3: Convert the charge separation (δ) to decimal fraction of the elementary charge (e).

To find the decimal fraction, divide δ by e:
δ(decimal fraction) = δ / e

Substituting the values:
δ(decimal fraction) = 6.96 x 10^9 C / 1.602 x 10^-19 C

δ(decimal fraction) ≈ 4.343 x 10^10

Therefore, the absolute value of the partial charge for CH as a decimal fraction of the elementary charge is approximately 4.343 x 10^10.