A spinner has three congruent sections labeled 1, 2, and 3. On the first two spins, the arrow stops on 1 and then 2. What is the probability that on the third spin the arrow will stop on 3?


A.1


B.2/3


C.1/3


D.0

A spinner has three congruent sections labeled 1, 2, and 3. On the first two spins, the arrow stops on 1 and then 2. What is the probability that on the third spin the arrow will stop on 3?

To find the probability of the arrow stopping on 3 on the third spin of the spinner, we need to consider the outcomes from the previous two spins.

Since the spinner has three congruent sections labeled 1, 2, and 3, each outcome on a single spin has a probability of 1/3.

On the first spin, the arrow stops on 1. This outcome has a probability of 1/3.

On the second spin, the arrow stops on 2. This outcome also has a probability of 1/3.

To find the probability of both events happening, we multiply their individual probabilities together.

So, the probability of the arrow stopping on 1 on the first spin and then 2 on the second spin is (1/3) * (1/3) = 1/9.

Now, we need to find the probability of the arrow stopping on 3 on the third spin. Since each section of the spinner is congruent and there are three sections in total, the probability of the arrow stopping on 3 on any given spin is 1/3.

However, the outcome of the third spin is independent of the outcomes of the previous spins. This means that the events do not affect each other, and the probability of the arrow stopping on 3 on the third spin is not affected by the previous outcomes.

Therefore, the probability of the arrow stopping on 3 on the third spin is still 1/3.

Hence, the answer is C. 1/3.

i need help

The third spin is independent, so the probability is 1/3.