10.5g of potassium trioxonitrate(v) salt saturated 5g of solvent at 15°c. Calculate the solubility of potassium trioxonitrate(v) salt at that same temperature in:
a)g/100g of solvents
b)moles per dm^-3
What is the chemical formula for potassium trioxonitrate(v)& potassium tetraoxosulphate.
10.5 g KNO3 in 5 g solvent. Convert to g KNO3/100 g solvent. That's 10.5 x 100/5 = ? g KNO3/100 g solvent
Isaac, you can convert grams solvent to dm-3 without knowing the density of the solvent
potassium trioxonitratev
KNO3 and K2SO
To calculate the solubility of the potassium trioxonitrate(V) salt at 15°C, we first need to understand the given information.
The amount of solute (potassium trioxonitrate(V) salt) is 10.5g, and the amount of solvent is 5g. This means that 10.5g of the salt was dissolved in 5g of the solvent.
a) To calculate the solubility in g/100g of solvent, we need to convert the given amounts to the desired unit:
Solubility (g/100g) = (Amount of Solute / Amount of Solvent) * 100
Plugging in the values, we get:
Solubility (g/100g) = (10.5g / 5g) * 100 = 210 g/100g
Therefore, the solubility of the potassium trioxonitrate(V) salt at 15°C is 210g/100g of solvent.
b) To calculate the solubility in moles per dm^-3, we need to convert the given amounts to moles.
First, we need to find the molar mass of the potassium trioxonitrate(V) salt. It consists of potassium (K), nitrogen (N), and oxygen (O).
K = 39.1 g/mol
N = 14.0 g/mol
O = 16.0 g/mol
The molar mass of potassium trioxonitrate(V) salt (KNO3) is:
(39.1 g/mol) + (14.0 g/mol) + (3 * 16.0 g/mol) = 101.1 g/mol
Now, we can calculate the solubility in moles per dm^-3:
Solubility (moles/dm^-3) = Amount of Solute (in g) / Molar Mass (in g/mol)
Plugging in the values, we get:
Solubility (moles/dm^-3) = 10.5g / 101.1 g/mol ≈ 0.104 mol/dm^-3
Therefore, the solubility of the potassium trioxonitrate(V) salt at 15°C is approximately 0.104 moles per dm^-3.