A student makes ice cream using an old-fashioned hand-crank machine. He does 40 joules of work each time he turns the crank in a complete circle. The crank handle makes a circular path with a diameter of 0.5 meters. The student turns the crank at a rate of once every 1.6 seconds.

Question

A student makes ice cream using an old-fashioned hand-crank machine. He does 40 joules of work each time he turns the crank in a complete circle. The crank handle makes a circular path with a diameter of 0.5 meters. The student turns the crank at a rate of once every 1.6 seconds.

What is the average power the student’s body produces to operate the machine?

Answer 1

power=work/time=40J*1/1.6second

power=40/1.6 watts

Answer 2

thank you very much

Answer 3

To find the average power the student's body produces to operate the machine, we need to determine the amount of work done per unit of time. Power is defined as the rate at which work is done.

First, we need to calculate the total work done by the student in one crank rotation. The work done is given as 40 joules.

Next, we need to determine the time it takes for the student to complete one crank rotation. The time given is 1.6 seconds.

Now, to calculate the average power, we divide the work done by the time taken:

Average Power = Work Done / Time Taken

Average Power = 40 joules / 1.6 seconds

Average Power = 25 watts

Therefore, the average power the student's body produces to operate the machine is 25 watts.

A student makes ice cream using an old-fashioned hand-crank machine. He does 40 joules of work each time he turns the crank in a complete circle. The crank handle makes a circular path with a diameter of 0.5 meters. The student turns the crank at a rate of once every 1.6 seconds.

power=work/time=40J*1/1.6second

thank you very much

fth

To find the average power the student's body produces to operate the machine, we need to determine the amount of work done per unit of time. Power is defined as the rate at which work is done.