A jug is 3/5 full of juice and if 100 ml is added to it it becomes 2/3 ful. How many literature can the jug hold?? Thanks a lot for hepl
3/5 x + 100 = 2/3 x
x is in mL
Now just solve for x. And that's liters, not literature!
Hey ;)
Good ol' dependence on "auto-correct"!! Proofreading is a must!
Well, it looks like we have a math problem disguised as a joke. Let's solve it, shall we?
If the jug is initially 3/5 full and adding 100 ml makes it 2/3 full, that means the 100 ml added fills up (2/3 - 3/5) = (10/15 - 9/15) = 1/15 of the jug.
So, if 100 ml is 1/15 of the jug's capacity, we can find the total capacity by multiplying both sides by 15/1:
100 ml * (15/1) = 1500 ml.
Therefore, the jug is capable of holding 1500 ml of juice!
Hope that puts a smile on your face!
To find out how many liters the jug can hold, we can follow these steps:
Step 1: Determine the initial volume of the juice in the jug.
If the jug is initially 3/5 full of juice, it means that 3/5 of the jug's capacity is filled with juice. Let's assign the variable x to represent the volume of the juice initially in the jug.
So, the equation representing this is:
x = (3/5) * jug_capacity
Step 2: Calculate the volume of the juice in the jug after adding 100 ml.
According to the problem, if 100 ml is added to the jug, it becomes 2/3 full. This means that the total volume of the juice and the added 100 ml is equal to 2/3 of the jug's capacity.
So, the equation representing this is:
x + 100 = (2/3) * jug_capacity
Step 3: Solve the equations simultaneously to find the jug's capacity.
We have two equations:
x = (3/5) * jug_capacity
x + 100 = (2/3) * jug_capacity
To solve for jug_capacity, we can substitute the value of x from the first equation into the second equation:
(3/5) * jug_capacity + 100 = (2/3) * jug_capacity
Now, we can solve for jug_capacity:
Multiply both sides of the equation by 15 to eliminate the denominators:
9 * jug_capacity + 1500 = 10 * jug_capacity
Rearrange the equation:
jug_capacity = 1500
Therefore, the jug can hold 1500 ml or 1.5 liters of juice.
Note: The initial volume of juice (x) is not specified in the problem, so we cannot determine the exact value in liters. We can only determine the jug's capacity.