describe how you prepare a 250cm3 of 0.5M solution Na2C03.indicate the variouse laboratory apparatus you will use

How many mols do you need? That's M x L = 0.5 x 0.250 = ?

Weigh out that many grams of Na2CO3, place in a 250 cc volumetric flask, add some distilled water and swirl until all of the Na2CO3 is dissolved, then add distilled water to the mark on the flask, stopper, mix thoroughly.

NACO3

To prepare a 250cm³ of 0.5M Na₂CO₃ (sodium carbonate) solution, you will need the following laboratory apparatus:

1. A balance: This is used to accurately measure the mass of the solid sodium carbonate required.

2. A volumetric flask (250cm³ capacity): This is used to mix and store the solution. It has a narrow neck with a mark that indicates the final volume.

3. A small beaker: This is used to weigh and transfer the required amount of sodium carbonate.

4. A stirring rod: This is used to mix the solid and the solvent.

5. A distilled water source: This is used as the solvent to dissolve the sodium carbonate.

Now, let's go through the step-by-step process of preparing the solution:

Step 1: Calculate the mass of sodium carbonate required. The molar mass of Na₂CO₃ is 105.99 g/mol (22.99 g/mol for Na, 12.01 g/mol for C, and 16.00 g/mol for O).

Mass (g) = Molarity (mol/L) × Volume (L) × Molar Mass (g/mol)
= 0.5 mol/L × 0.25 L × 105.99 g/mol
= 13.24875 g (rounded to approximately 13.25 g)

Step 2: Use the balance to measure approximately 13.25 g of sodium carbonate in the small beaker.

Step 3: Transfer the sodium carbonate into the volumetric flask.

Step 4: Add distilled water to the volumetric flask until it reaches approximately the 250cm³ mark.

Step 5: Use the stirring rod to mix the solution thoroughly until all of the sodium carbonate dissolves.

Step 6: Once the sodium carbonate is completely dissolved, continue adding distilled water until the bottom of the meniscus reaches exactly the 250cm³ mark.

Step 7: Place the stopper on the volumetric flask and invert it several times to ensure complete mixing.

Congratulations! You have successfully prepared a 250cm³ of 0.5M Na₂CO₃ solution.

To prepare a 250cm3 (also known as 250mL) of 0.5M sodium carbonate (Na2CO3) solution, you will need the following laboratory apparatus:

1. Analytical balance: Use an analytical balance to accurately measure the required amount of sodium carbonate.

2. Weighing boat or container: Place the sodium carbonate in a weighing boat or container on the balance.

3. Graduated cylinder: Use a graduated cylinder to measure the appropriate volume of water needed for the solution.

4. Volumetric flask: A volumetric flask is a specialized flask used for accurately preparing solutions of a specific volume. In this case, you will need a 250mL volumetric flask.

Here's how you can prepare the solution:

1. Calculate the mass of sodium carbonate needed: To prepare a 0.5M solution, you need to know the molar mass of sodium carbonate (105.99g/mol) and the desired volume (250mL). The formula for calculating the mass required is:

Mass (g) = Molarity (mol/L) x Volume (L) x Molar mass (g/mol)

Plugging in the values, you get:
Mass (g) = 0.5 mol/L x 0.25 L x 105.99 g/mol

Calculate the mass required using this equation.

2. Weigh the sodium carbonate: Once you have determined the mass, use an analytical balance to accurately measure that quantity of sodium carbonate.

3. Dissolve in water: Transfer the weighed sodium carbonate to the volumetric flask. Then, add some distilled water to dissolve the solid. Swirl the flask gently until the sodium carbonate is completely dissolved.

4. Fill to the mark: Add more distilled water to the volumetric flask until the solution reaches the mark on the neck of the flask. Be careful not to exceed or fall short of the mark. Hold the flask at eye level to ensure accuracy.

5. Mix thoroughly: Cap the volumetric flask and invert it several times to mix the solution thoroughly.

Now, you have prepared a 250cm3 (250mL) of 0.5M sodium carbonate solution. Remember to label it properly and store it appropriately if not using immediately.