a box with a mass of 25kg is lifted (without acceleration) through a height of 2.0m, in order to place it upon the shelf of a closet. The value of acceleration due to gravity g= 9.8ms^2
How much work is required to lift the box to this position? i figured out the potential energy and i got 490J PE=mgh but how do i figure out the work. w=f X d
the work must equal the PE gained by the box.
so would it look like this 490= f x 2.0
245J ??
PEgained=m*g*height=25kg*9.8N/kg*2m
that is not 245J.
If you insist on f x d, the force is weight: 25*9.8=you do it N
and d is 2 m
again, work is equal to the PE gained.
122.5J ? when your saying work is equal to the PE gained. does that mean its 490j??
i got it bob thanks lol should be 490J!!
PE=mgh
Work done against gravity =mgh
PE=Work Done
To calculate the work done in lifting the box, you can use the equation W = F * d, where W is the work done, F is the force applied, and d is the displacement.
In this case, you can calculate the force applied using the equation F = m * g, where m is the mass of the box and g is the acceleration due to gravity.
Given that the mass of the box is 25 kg and the value of acceleration due to gravity is 9.8 m/s^2, you can compute the force applied as follows:
F = m * g
F = 25 kg * 9.8 m/s^2
F = 245 N
Now that you have the force applied (245 N) and the displacement (2.0 m), you can calculate the work done:
W = F * d
W = 245 N * 2.0 m
W = 490 J
Therefore, the work required to lift the box to a height of 2.0 m is 490 Joules (J).