We will calculate the amount of acid to use in each titration. Assume that you are using 0.0512 M NaOH(aq). A good volume of NaOH(aq) to use per titration is 15 mL. From this molarity and volume, the moles of NaOH can be calculated. Since the unknown acid is monoprotic, this also equals the number of moles of acid to use. A typical molar mass for an unknown acid in this experiment is 380 g/mol. Using this molar mass, calculate the mass (in grams) of unknown acid you should use per titration. Since we have been estimating values, round your answer to two significant figures

mols NaOH = M x L = ?

mols HCl = mols NaOH (from the problem)
mols acid = grams/molar mass. You know molar mass and mols acid, solve for grams acid. Round to two s.f.

.29

Well, if the unknown acid is feeling a bit lost, we can help them find their way with some good old calculations! Now, we know that the molarity of the NaOH solution is 0.0512 M, and we want to use 15 mL of it. So, let's calculate the moles of NaOH first.

Moles of NaOH = Molarity × Volume = 0.0512 M × 0.015 L = 0.000768 moles

Since the unknown acid is monoprotic, the number of moles of acid to use is also 0.000768 moles. And if the typical molar mass for the unknown acid is 380 g/mol, we can calculate the mass of acid.

Mass of acid = Moles of acid × Molar mass = 0.000768 moles × 380 g/mol = 0.292 g

Now, let's round that answer to two significant figures, just to keep things happy. So, you should use approximately 0.29 grams of unknown acid per titration.

Ta-da! The acid's got some serious mass going on now.

To calculate the mass of unknown acid to use per titration, we need to use the given molarity and volume of NaOH(aq) and the molar mass of the unknown acid.

First, let's calculate the moles of NaOH used per titration:
moles of NaOH = molarity of NaOH x volume of NaOH
moles of NaOH = 0.0512 M x 15 mL

Since 1 mL is equal to 0.001 L, we convert the volume of NaOH to liters:
15 mL x 0.001 L/mL = 0.015 L

Now we can calculate the moles of NaOH:
moles of NaOH = 0.0512 M x 0.015 L

Next, we need to determine the moles of acid used per titration. Since the unknown acid is monoprotic, the moles of NaOH will also equal the moles of acid to use in this case.

Now, to calculate the mass of the unknown acid, we use the following formula:

mass of unknown acid = moles of acid x molar mass of unknown acid

Given that the molar mass of the unknown acid is 380 g/mol, we can substitute the values:

mass of unknown acid = moles of acid x 380 g/mol

Finally, we substitute the moles of NaOH into the equation to calculate the mass of the unknown acid per titration:

mass of unknown acid = (0.0512 M x 0.015 L) x 380 g/mol

By performing the calculation, we find:

mass of unknown acid = 0.03672 g

Rounding this value to two significant figures, the mass of unknown acid to use per titration is 0.037 g.