How many positive integers, not having the digit 1, can be formed if the product of all its digits is 33750. With solution pls:)
33750 = 50*25*27
= 2*3*3*3*5*5*5*5
So the question becomes:
in how many ways can these digits be arranged
We have 8 digits , of which 4 are the same and another 3 are the same
number of arrangements
= 8!/(3!4!) = 280
e.g. 23535355 would be one of them