A car traveling at 25 mi/h accelerates to 48 mi/h over the first 5 seconds. It maintains that speed for the next 5 seconds, and then slows to a stop during the next 5 seconds. Connections answers please?
By the way, the answer is B.
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Well, this car is quite the speed demon! Let's break down its journey and see what connections we can make.
In the first 5 seconds, the car accelerates from 25 mi/h to 48 mi/h. That's a pretty impressive jump! It's like going from a leisurely stroll to a full-on sprint. If you were to ask the car how it did that, it would probably say, "I floored it and left skid marks behind!"
Now, during the next 5 seconds, the car maintains a speed of 48 mi/h. It's like finding that sweet spot of momentum where you're cruising along effortlessly. The car would probably say, "Ah, the wind is blowing through my metaphorical hair; life is good."
But, alas, all good things must come to an end. In the final 5 seconds, the car slows down and eventually comes to a stop. It's like going from a thrilling roller coaster ride to waiting in line for cotton candy. The car might say, "Well, time to take a break and catch my breath. My brakes deserve a standing ovation!"
So, to sum it up, this car goes from a reasonable speed, accelerates like a maniac, maintains a steady pace, and gracefully comes to a stop. Quite the journey, wouldn't you say?
To solve this problem, we can use the formulas of motion under constant acceleration. Let's break down the problem into three parts: acceleration, uniform motion, and deceleration.
1. Acceleration:
The car starts from 25 mi/h and accelerates to 48 mi/h over the first 5 seconds. We can calculate the acceleration using the formula:
acceleration = (final velocity - initial velocity) / time
Substituting the given values:
acceleration = (48 mi/h - 25 mi/h) / 5 s
acceleration = 23 mi/h / 5 s
acceleration = 4.6 mi/h/s
2. Uniform Motion:
The car maintains a speed of 48 mi/h for the next 5 seconds. Since there is no change in velocity, the acceleration during this period is 0 mi/h/s.
3. Deceleration:
The car slows down from 48 mi/h to a stop during the next 5 seconds. Since the final velocity is 0 and the initial velocity is 48 mi/h, we can calculate the deceleration using the same formula as before:
deceleration = (final velocity - initial velocity) / time
Substituting the values:
deceleration = (0 - 48 mi/h) / 5 s
deceleration = -48 mi/h / 5 s
deceleration = -9.6 mi/h/s
Therefore, the car decelerates at a rate of -9.6 mi/h/s.
To summarize:
- The car accelerates at a rate of 4.6 mi/h/s for the first 5 seconds.
- It maintains a speed of 48 mi/h for the next 5 seconds with no acceleration.
- Finally, it decelerates at a rate of -9.6 mi/h/s for the last 5 seconds.
Is there a question here?
Connections doesn't seem to be the answer.