What is the equation of the line that has a slope of -2 and a y-intercept of -7?
y = -2x - 7
y = -7x - 2 <-
y = -2x + 7
y = -7x + 2
Find the equation of the line that has a slope of 4 and contains the point (-4, 1).
y = 4x + 1
y = 4x - 8
y = 4x - 15 <--
y = 4x + 17
Find the equation of the line that passes through the point (1,5) and has a slope of -2.
y = -2x + 7 <-- im not sure
y = -2x + 11
y = 2x - 9 or <--
y = 2x + 3
Which equation represents the line that passes through the points (-3,7) and (3,3)?
y=2/3x+1
y=2/3x+9 <-- im not sure on the last two.
y=-2/3x+9
y=-2/3x+5
I'm trying
nope, all wrong. Let me give you a link to solving these. Take a few minutes and watch this:
https://www.khanacademy.org/math/algebra/two-var-linear-equations/writing-slope-intercept-equations/v/linear-equations-in-slope-intercept-form
Then on the left, if you wish, there are some practice problems.
Make sure you go thru the entire video, you need to understand this....and it is not hard.
to determine the equation of the line that passes through the given points. To do this, we can use the point-slope form of a linear equation, which is:
y - y1 = m(x - x1)
where (x1, y1) are the coordinates of a point on the line, and m is the slope of the line.
For the given points (-3,7) and (3,3), let's use the point (-3,7) to find the equation.
First, we need to find the slope (m) of the line using the formula:
m = (y2 - y1) / (x2 - x1)
Let's substitute the coordinates into this formula:
m = (3 - 7) / (3 - (-3)) = -4 / 6 = -2/3
Now, we have the slope of the line (-2/3) and a point on the line (-3,7). We can substitute these values into the point-slope form and simplify to find the equation of the line:
y - 7 = -2/3(x - (-3))
y - 7 = -2/3(x + 3)
3(y - 7) = -2(x + 3)
3y - 21 = -2x - 6
3y = -2x + 15
y = -2/3x + 5
So, the equation of the line that passes through the points (-3,7) and (3,3) is y = -2/3x + 5.