Gent dose at 10:26am over 30 minutes and levels were reported as 3.6 at 13:07 and 1.2 at 16:59. Calculate k.
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K=ln(3.6/1.2)/timeelapsed
k=ln(3)/(1307-1056)=ln(3)/2:11
k= ln(3)/(131min) or ln3/2.18 hr
K=0.50 is this correct?
yes, but you need to include units:
.50/hr
Thank you!
To calculate the rate constant (k) for drug elimination, we can use the first-order elimination equation:
C(t) = C(0) * e^(-kt)
where C(t) is the drug concentration at time t, C(0) is the initial drug concentration, e is the base of the natural logarithm (approximately 2.71828), k is the rate constant, and t is the time.
In this case, we are given three data points:
- At 10:26 am (t=0), the drug concentration is not provided.
- At 13:07 (t = 2 hours and 41 minutes), the drug concentration is reported as 3.6.
- At 16:59 (t = 6 hours and 33 minutes), the drug concentration is reported as 1.2.
To calculate k, we need to know the initial drug concentration, C(0), at 10:26 am. Without this information, it is not possible to calculate the rate constant accurately.
Please make sure you have provided all the necessary data or consult the source from which you obtained the information to find the initial drug concentration at 10:26 am.