5x - 4y =-3
Y = -3x + 5
Solve for x and y
How do we solve for x and y when the formats of the equations are different. That's we here I'm lost. When I try to get the answer I get confused
so the formats are different. So what? Rearrange them so they are the same!
5x - 4y = -3
3x + y = 5
Now you can manipulate them.
Or, since you know that y = -3x+5, use that in the other equation:
5x - 4(-3x+5) = -3
Solve for x, and then get y.
So would it be
5(1) -4y (-3(1)+5)= -3
Y=1 ??
To solve the system of equations:
5x - 4y = -3 .............(Equation 1)
y = -3x + 5 .............(Equation 2)
First, let's convert Equation 2 into slope-intercept form (y = mx + b), where m represents the slope and b represents the y-intercept. By rearranging the equation, we have:
y = -3x + 5
Now, we can see that the slope of Equation 2 is -3, meaning that for every increase of 1 in x, y will decrease by 3.
To solve for x and y, we will substitute Equation 2 into Equation 1.
Replace y in Equation 1 with the right side of Equation 2:
5x - 4(-3x + 5) = -3
Simplify the expression:
5x + 12x - 20 = -3
Combine like terms:
17x - 20 = -3
To isolate x, add 20 to both sides of the equation:
17x = 17
Now, divide both sides of the equation by 17 to solve for x:
x = 1
Next, substitute the value of x back into Equation 2 to solve for y:
y = -3(1) + 5
y = -3 + 5
y = 2
So, the solution to the system of equations is x = 1 and y = 2.