How many mole of CL2 are needed to react with 2.0 mole Na?
2Na + Cl2 ==> 2NaCl
2 mols Na x (1 mol Cl2/2 mols Na) = 2*1/2 = ?
To determine the number of moles of Cl2 needed to react with 2.0 moles of Na, we need to use the balanced chemical equation for the reaction between Cl2 and Na.
The balanced chemical equation for the reaction is:
2 Na + Cl2 -> 2 NaCl
From the equation, we can see that 1 mole of Cl2 reacts with 2 moles of Na.
Therefore, if we have 2.0 moles of Na, we can calculate the moles of Cl2 needed as follows:
moles of Cl2 = (moles of Na) / (stoichiometric coefficient of Na)
moles of Cl2 = 2.0 moles Na / 2 = 1.0 mole
Thus, 1.0 mole of Cl2 is needed to react with 2.0 moles of Na.
To determine the number of moles of Cl2 needed to react with 2.0 moles of Na, we need to examine the balanced chemical equation for the reaction between Cl2 and Na.
The balanced chemical equation for the reaction is:
2Na + Cl2 → 2NaCl
From the balanced equation, we can see that 1 mole of Cl2 reacts with 2 moles of Na to form 2 moles of NaCl.
So, if we have 2.0 moles of Na, we would need half as many moles of Cl2. Therefore, we would need 1.0 mole of Cl2 to react with 2.0 moles of Na.