A heterozygous brown eyed (Bb) parent and a homozygous brown eyed parent (BB) have offspring. Which of these genotypes would not occur in their offspring?

A. bb
B. Bb
C. BB

Not positive but A?

To determine which genotype would not occur in their offspring, we need to understand how traits are inherited through genetics.

The letter "B" represents the dominant allele for brown eyes, while the lowercase letter "b" represents the recessive allele for blue eyes. In this scenario, the heterozygous brown-eyed parent (Bb) has one copy of the dominant allele and one copy of the recessive allele, while the homozygous brown-eyed parent (BB) has two copies of the dominant allele.

When two individuals with genotypes Bb and BB have offspring, there are four possible combinations of alleles that the offspring can inherit: BB, Bb, BB, and bb.

Now, let's analyze the answer choices:

A. bb: This genotype represents a homozygous recessive individual with two copies of the recessive allele for blue eyes. Since one parent has the dominant allele (Bb) and the other parent has two dominant alleles (BB), this genotype (bb) will not occur in their offspring.

B. Bb: This genotype represents a heterozygous individual with one copy of the dominant allele and one copy of the recessive allele for brown eyes. Since one parent has the dominant allele (Bb) and the other parent has two dominant alleles (BB), this genotype (Bb) is possible in their offspring.

C. BB: This genotype represents a homozygous dominant individual with two copies of the dominant allele for brown eyes. Since one parent has the dominant allele (Bb) and the other parent has two dominant alleles (BB), this genotype (BB) is possible in their offspring.

Based on this analysis, the genotype that would not occur in their offspring is A. bb.

Therefore, your answer of A is correct.

it might be c if its not right correct me please!!

Do a Punnett square. Amber is right.

Thank you!

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