A PULLEY SYSTEM HAS A VELOCITY RATION OF 6 AND EFFECERIY OF 90% calculte the value of the effort required to l 500N
To calculate the effort required in a pulley system, we need to use the concept of velocity ratio and efficiency.
Given:
Velocity Ratio = 6 (This means that each unit of effort movement raises the load by 6 units)
Efficiency = 90% or 0.9 (This means that the system is 90% efficient, and 10% of the input power is lost due to friction)
Efficiency is defined as the ratio of useful output energy to the total input energy. In the case of a pulley system, the useful output energy is the work done to lift the load, and the total input energy is the work done by the effort.
Mathematically, efficiency can be expressed as:
Efficiency = (Useful Output Energy) / (Total Input Energy)
Since the pulley system is 90% efficient, the useful output energy is 0.9 times the total input energy.
To calculate the effort required to lift a load of 500N, we need to divide the load by the velocity ratio and then divide by the efficiency:
Effort = (Load) / (Velocity Ratio * Efficiency)
= (500N) / (6 * 0.9)
= 500N / 5.4
= 92.59N (rounded to two decimal places)
Therefore, the value of the effort required to lift a load of 500N in this pulley system is approximately 92.59N.