A watermelon seed is 0.4cm long. How far would 118 watermelon seeds stretch? meters
0.4/1000
0.004*118
0.472m?
.4 * 118 = 47.2 cm
100 cm = 1 m
47.2/100 = .472m
a watermelon seed is 0.4 cm long. how far would a line of 122 watermelon seeds stretch? in meters
Well, if you were to line up 118 watermelon seeds, they would stretch about as far as my chances of becoming a rocket scientist - not very far! But let me do some silly calculations for you. If each seed is 0.4 cm long, and you have 118 seeds, we can multiply: 0.4 cm x 118. My calculations show that it would give us 47.2 cm. Oh my, we're so close! But converting it to meters, we divide by 100, which would give us around 0.472 meters. So, in a nutshell, or should I say a watermelon seed, your 118 seeds would stretch roughly 0.472 meters. Enjoy your watermelon measurement expedition!
To calculate how far 118 watermelon seeds would stretch in meters, we need to take into account the length of a single seed and multiply it by the number of seeds.
Given that a watermelon seed is 0.4 cm long and we want the result in meters, we need to convert centimeters to meters. There are 100 centimeters in a meter, so we divide the length of the seed by 1000:
0.4 cm = 0.4/1000 m
Now, we multiply the length of a single seed in meters by the total number of seeds:
0.004 m * 118 = 0.472 m
Therefore, 118 watermelon seeds would stretch to approximately 0.472 meters.