In a basket of fruit, there are 6 grapes,11 bananas and 13 oranges, if one fruit is chosen at random, what is the probability that the fruit is either grape or banana.
i.find the probability of grape and banana
i.find the probability of not banana
of the 30 fruits, how many are "either grape or banana" ?
How many are "not bananas" ?
To find the probability that the fruit is either a grape or a banana, we need to determine the probabilities of each fruit separately and then add them together.
First, let's find the probability of selecting a grape. We have 6 grapes out of a total of 6 + 11 + 13 = 30 fruits in the basket. Therefore, the probability of selecting a grape is 6/30.
Next, let's find the probability of selecting a banana. We have 11 bananas out of a total of 30 fruits in the basket. Thus, the probability of selecting a banana is 11/30.
To find the probability of either a grape or a banana, we add the probabilities together: (6/30) + (11/30) = 17/30.
Therefore, the probability that the fruit selected is either a grape or a banana is 17/30.
Now, let's find the probability of not picking a banana. There are 11 bananas out of a total of 30 fruits in the basket. Therefore, the probability of not picking a banana is 1 - (11/30) = (30/30) - (11/30) = 19/30.