How much heat is absorbed by a 30g iron skillet when its temperature rises from 24oC to 93oC?
Joules
do i addition everything?
mass * temp change * specific heat
make sure the specific heat value is in Joules
To calculate the amount of heat absorbed by the iron skillet, you can use the formula:
Q = m * c * ΔT
Where:
Q is the heat absorbed (in Joules)
m is the mass of the skillet (in grams)
c is the specific heat capacity of iron (in J/g°C)
ΔT is the change in temperature (in °C)
First, convert the mass from grams to kilograms:
30 g = 0.03 kg
Next, find the specific heat capacity of iron. The specific heat capacity of iron is approximately 0.45 J/g°C.
Now, substitute the values into the formula:
Q = 0.03 kg * 0.45 J/g°C * (93°C - 24°C)
Q = 0.03 kg * 0.45 J/g°C * 69°C
Q = 0.6207 J
Therefore, the amount of heat absorbed by the iron skillet when its temperature rises from 24°C to 93°C is approximately 0.6207 Joules.