If each of the sides of an isoceles triangle is 5 x the size of the baseline and the perimeter of the triangle is 121 cm, how many centimeters is each of the sides of the triangle? I have the sides at 50 cm and the base at 21cm. ?
5 b + 5 b + b = 121
To find the length of each side of the triangle, we can set up an equation using the given information. Let's assume that the baseline of the triangle is represented by the variable 'x'. According to the given information, each side of the triangle is 5 times the size of the baseline, so the length of each side can be represented by '5x'.
The perimeter of a triangle is the sum of the lengths of all its sides. In this case, the perimeter is given as 121 cm. So we can write the equation as:
x + 5x + 5x = 121
Now, we can solve this equation to find the value of 'x', which represents the length of the baseline. Combining like terms on the left side of the equation:
11x = 121
Dividing both sides of the equation by 11:
x = 121/11
x = 11
So, the length of the baseline is 11 cm. Since each side of the triangle is 5 times the size of the baseline, the length of each side is:
5x = 5 * 11 = 55 cm
Therefore, each side of the triangle is 55 cm, not 50 cm as you mentioned.