All the members of a construction crew work at the same pace. Four of them working together are able to pour concrete foundations in 32 hours. How many hours would this job take if the number of workers decreased 2 times?
actually 64 hours
64 hours
To solve this problem, we can use the concept of "worker-hours". Worker-hours is the product of the number of workers and the amount of time they work. Let's break down the information given:
1. We know that four workers can complete the job of pouring concrete foundations in 32 hours. This means that together, they accumulate 4 worker-hours per hour.
- So, in one hour, four workers complete 4 worker-hours.
2. Now, let's denote the total number of workers as "N".
- N workers will complete N worker-hours per hour.
3. We want to find the number of hours it would take if the number of workers decreased by 2 times (i.e., reduced by half). So, there would be N/2 workers.
- N/2 workers would complete (N/2) worker-hours per hour.
To determine the time it would take for N/2 workers to complete the job, we can set up the following equation:
(N/2) worker-hours per hour = 4 worker-hours per hour
Solving for N, we can find the number of workers needed for the job to be completed in the same amount of time:
(N/2) = 4
Multiply both sides of the equation by 2:
N = 8
Therefore, if the number of workers decreased by 2 times, the job would take 8 workers.
44 hours
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