Two point charges each have a value of 3 μC and are 10 cm apart. What is the electric field at the midpoint between the two charges?
Both postive? The E field from each charge is equal an opposite in direction, net field:zero
a pendulum bob has by passing through its lowest position. what is its speed when make angle of 60 with the vertical the length of the pendulum is 0.5 .
To find the electric field at the midpoint between the two charges, we can use the principle of superposition. The electric field created by each individual charge will add up at the midpoint.
First, let's calculate the electric field created by each charge separately using Coulomb's law:
Coulomb's Law states that the electric field created by a point charge at a distance r is given by:
E = (k * q) / r^2
Where:
E is the electric field
k is the electrostatic constant (9 x 10^9 Nm^2/C^2)
q is the charge of the point charge
r is the distance between the point charge and the location where you want to find the electric field
Given that the charge of each point charge is 3 μC (3 x 10^(-6) C) and the distance between them is 10 cm (0.1 m), we can calculate the electric field created by each charge at the midpoint.
For the first point charge:
q1 = 3 x 10^(-6) C
r1 = 0.05 m (half the distance between the point charges, as we want to find the field at the midpoint)
Using Coulomb's law, we get:
E1 = (k * q1) / r1^2
For the second point charge:
q2 = 3 x 10^(-6) C
r2 = 0.05 m (half the distance between the point charges, as we want to find the field at the midpoint)
Using Coulomb's law, we get:
E2 = (k * q2) / r2^2
To find the electric field at the midpoint, we add the two electric fields together:
E_total = E1 + E2
You can now calculate the electric field at the midpoint by substituting the values into the equations.
Note: The electric field will have both magnitude and direction. The direction will depend on the sign of the charges and the orientation of the coordinate system.