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Find the slope intercept form of the line passing through the point (-5,-7) and parallel to the line 4x+2y=-2

Eq1: 4x + 2y = -2.

m1 = -A/B = -4/2 = -2.

m2 = m1 = -2. P2 = (-5,-7).

Y = mx + b = -7,
-2x + b = -7, b = -7+2x = -7 + 2(-5) = -17.

Eq2:Y = -2x - 17.

Did you know?

Did you know that the slope intercept form of a line is given by y = mx + b, where m represents the slope and b represents the y-intercept? To find the slope intercept form of a line parallel to another line, we first need to find the slope of the given line. In this case, the given line is 4x + 2y = -2. By rearranging the equation to solve for y, we get y = -2x -1. Thus, the slope of the given line is -2. Since the line we want to find is parallel to this line, it will also have a slope of -2. Now we can use the slope (-2) and the point (-5,-7) to find the equation of the line using the slope intercept form. By substituting the values into y = mx + b, we get -7 = -2(-5) + b. Solving for b, we find that b = -17. Therefore, the slope intercept form of the line parallel to 4x + 2y = -2 and passing through the point (-5,-7) is y = -2x - 17.