A student reduces the temperature from a 300 cm3 balloon from 60°C to 20°C. What will the new volume of the balloon be?
264 cm3 <my answer choice
100 cm3
300 cm3
341 cm3
v=300*(273+20)/(273+60)
you dont need to do math, the only volume below 300 is answer a.
To solve this problem, we can use Charles's law, which states that the volume of a gas is directly proportional to its temperature, assuming the pressure and amount of gas remain constant.
According to Charles's law, if the temperature decreases, the volume will also decrease.
We can use the formula:
(V1/T1) = (V2/T2)
Where:
V1 = initial volume (300 cm^3)
T1 = initial temperature (60°C + 273.15 = 333.15 K)
V2 = final volume (unknown)
T2 = final temperature (20°C + 273.15 = 293.15 K)
Now substitute the values into the equation:
(300 cm^3 / 333.15 K) = (V2 / 293.15 K)
Cross-multiplying, we get:
V2 = (300 cm^3 × 293.15 K) / 333.15 K
Simplifying further:
V2 = (87945 cm^3·K) / 333.15 K
V2 ≈ 263.8 cm^3
So, the new volume of the balloon would be approximately 263.8 cm^3.
Therefore, the correct answer choice is 264 cm^3.
To find the new volume of the balloon after reducing the temperature, we can use Charles' Law, which states that the volume of a gas is directly proportional to its temperature, assuming constant pressure.
The formula for Charles' Law is:
V1/T1 = V2/T2
Where:
V1 = Initial volume (300 cm3)
T1 = Initial temperature (60°C + 273.15 = 333.15 K)
V2 = Final volume (unknown)
T2 = Final temperature (20°C + 273.15 = 293.15 K)
Now we can plug in the values into the formula and solve for V2:
V1/T1 = V2/T2
300 cm3 / 333.15 K = V2 / 293.15 K
Cross multiplying:
V2 = (300 cm3 * 293.15 K) / 333.15 K
V2 = 264 cm3
Therefore, the new volume of the balloon will be 264 cm3. So the correct answer is "264 cm3".