The molecular formula of 2.68g hydrated sodium sulphate is Na2SO4.nH2O.If the mass loss on heating is 1.26g then calculate the value of n.

Well, if the hydrated sodium sulphate loses 1.26g on heating, it means that the water molecules are being kicked out of the compound like they're late for a water party.

Now, to calculate the value of n, we can first find the molar mass of the hydrated sodium sulphate. The molar mass of Na2SO4 is approximately 142.04 g/mol, and the molar mass of H2O is about 18.02 g/mol.

We can set up an equation using the given information:

2.68g (total mass) - 1.26g (mass loss from heating) = 2.68g - 1.26g (mass of hydrated sodium sulphate left after heating)

Now, we need to find the number of moles of hydrated sodium sulphate left after heating. To do that, we divide the mass by the molar mass:

1.42g (mass of hydrated sodium sulphate left after heating) / 142.04 g/mol (molar mass of Na2SO4) = 0.01 mol

Now, we know that each mole of hydrated sodium sulphate contains "n" moles of water. So, 0.01 mol of hydrated sodium sulphate contains "n" moles of water.

Therefore, the value of n is 0.01. So, it's like "n" came fashionably late to the water party. I hope that answers your question with a side of humor!

To determine the value of n, we need to calculate the molar mass of the hydrated sodium sulfate and the mass of water lost during heating.

Step 1: Calculate the moles of hydrated sodium sulfate.
Molar mass of Na2SO4 = (2 x atomic mass of Na) + atomic mass of S + (4 x atomic mass of O)
= (2 x 22.99) + 32.07 + (4 x 16.00)
= 45.98 + 32.07 + 64.00
= 142.05 g/mol

Moles of hydrated sodium sulfate = mass of Na2SO4 / molar mass of Na2SO4
= 2.68 g / 142.05 g/mol
≈ 0.0189 mol

Step 2: Calculate the moles of water lost during heating.
Moles of water lost = mass loss on heating / molar mass of water
= 1.26 g / 18.02 g/mol
≈ 0.070 mol

Step 3: Calculate the value of n.
The formula for hydrated sodium sulfate is Na2SO4.nH2O. This means that for every formula unit of Na2SO4, there are n moles of water.
Using the mole ratio between Na2SO4 and water:
0.0189 mol Na2SO4 corresponds to 0.0189 x n mol water.

Since 0.070 mol of water is lost during heating:
0.0189 x n = 0.070
n ≈ 3.7

Therefore, the value of n is approximately 3.7.

To calculate the value of n, we need to determine the amount of water (H2O) molecules present in the hydrated sodium sulfate compound.

Step 1: Calculate the number of moles of hydrated sodium sulfate.
First, we need to find the molar mass of Na2SO4.
Molar mass of Na = 22.99 g/mol
Molar mass of S = 32.06 g/mol
Molar mass of O = 16.00 g/mol

Molar mass of Na2SO4 = (2 * 22.99) + 32.06 + (4 * 16.00)
= 45.98 + 32.06 + 64.00
= 142.04 g/mol

Next, we need to calculate the number of moles of hydrated sodium sulfate:
Number of moles = Mass (g) / Molar mass (g/mol)
Number of moles of Na2SO4 = 2.68 g / 142.04 g/mol

Step 2: Calculate the number of moles of water lost.
Since the mass loss on heating is due to the loss of water, we can calculate the number of moles of water lost using the mass lost.

Number of moles of water lost = Mass lost (g) / Molar mass of water (g/mol)
Number of moles of water lost = 1.26 g / 18.02 g/mol

Step 3: Find the value of n.
The value of n represents the ratio of moles of water to moles of hydrated sodium sulfate. Therefore, we can equate the number of moles of water lost to n and the number of moles of sodium sulfate.

Number of moles of water lost = n
Number of moles of Na2SO4 = 2.68 g / 142.04 g/mol

So, we have the equation:
1.26 g / 18.02 g/mol = n / (2.68 g / 142.04 g/mol)

To find n, we can rearrange the equation:
n = (1.26 g / 18.02 g/mol) * (2.68 g / 142.04 g/mol)
n = 0.0887

Therefore, the value of n is approximately 0.0887.

figure the moles of the hydrated molecule in (2.68-1.26) grams of Na2SO4

then, figure the moles of H2O in 1.26.

the ratio of the second to the first is n