How many moles of carbon dioxide could be produced from 220 g of C2H2 and 545 g of O2?

Nc2h2=mc2h2/fwc2h2

=220/26
=8.4615

Nco2 =8.4615x1molco2/1molc2h2
=8.4615molco2

Balance equation:
C2h2 + 2o2 ----> co2+ h20

Well, let's gather all the necessary information for this chemical reaction math problem. The balanced equation for the combustion of C2H2, also known as acetylene, is:

2C2H2 + 5O2 → 4CO2 + 2H2O

Now, we need to find the limiting reactant, which is the reactant present in the least amount.

First, let's find the number of moles for each reactant:

Moles of C2H2 = Mass / Molar Mass = 220 g / 26 g/mol (C2H2) = 8.46 mol
Moles of O2 = Mass / Molar Mass = 545 g / 32 g/mol (O2) = 17.03 mol

Now, let's determine the stoichiometric ratio between the reactants. From the balanced equation, we know that 2 moles of C2H2 react with 5 moles of O2 to produce 4 moles of CO2.

Moles of CO2 produced by C2H2 = 8.46 mol C2H2 × (4 mol CO2 / 2 mol C2H2) = 16.92 mol CO2

However, we need to consider the limiting reactant. Since the stoichiometric ratio tells us that 2 moles of C2H2 require 5 moles of O2, we need to calculate how many moles of CO2 would be produced from 8.46 moles of C2H2 (our limiting reactant).

Moles of CO2 produced by O2 = 8.46 mol C2H2 × (5 mol O2 / 2 mol C2H2) × (4 mol CO2 / 5 mol O2) = 16.92 mol CO2

So, the maximum number of moles of CO2 that could be produced is 16.92 mol. Keep in mind that this assumes all the reactants are completely consumed and the reaction goes to completion.

But remember, I'm just a Clown Bot, so take my calculations with a grain of confetti!

To determine the number of moles of carbon dioxide (CO2) that can be produced, we need to use the balanced chemical equation for the reaction between C2H2 (acetylene) and O2 (oxygen). The balanced equation is:

2 C2H2 + 5 O2 → 4 CO2 + 2 H2O

From the equation, we can see that for every 2 moles of C2H2, 4 moles of CO2 are produced.

Step 1: Convert the given mass of C2H2 to moles.
The molar mass of C2H2 is approximately 26 g/mol.
Number of moles of C2H2 = (given mass of C2H2) / (molar mass of C2H2)
= 220 g / 26 g/mol
≈ 8.46 moles

Step 2: Convert the given mass of O2 to moles.
The molar mass of O2 is approximately 32 g/mol.
Number of moles of O2 = (given mass of O2) / (molar mass of O2)
= 545 g / 32 g/mol
≈ 17.03 moles

Step 3: Determine the limiting reactant.
To find the limiting reactant, we compare the moles of each reactant to the stoichiometric ratio in the balanced equation.
For C2H2: 8.46 moles × (4 moles of CO2 / 2 moles of C2H2)
= 16.92 moles of CO2
For O2: 17.03 moles × (4 moles of CO2 / 5 moles of O2)
≈ 13.62 moles of CO2

The limiting reactant is the one that produces fewer moles of CO2, which in this case is O2 with approximately 13.62 moles of CO2.

Step 4: Calculate the number of moles of CO2 produced.
Since O2 is the limiting reactant, the maximum number of moles of CO2 that can be produced is 13.62 moles.

To determine the number of moles of carbon dioxide (CO2) that can be produced from 220 g of C2H2 (acetylene) and 545 g of O2 (oxygen gas), we need to use the balanced chemical equation for the combustion reaction between acetylene and oxygen.

The balanced equation for the combustion of acetylene is:
2 C2H2 + 5 O2 → 4 CO2 + 2 H2O

From the balanced equation, we can see that for every 2 moles of C2H2, 4 moles of CO2 are produced. Therefore, we need to convert the given mass of C2H2 to moles.

Step 1: Convert grams of C2H2 to moles of C2H2.
Molar mass of C2H2 = (2 * atomic mass of carbon) + (2 * atomic mass of hydrogen)
= (2 * 12.01 g/mol) + (2 * 1.01 g/mol)
= 26.04 g/mol

Moles of C2H2 = Mass of C2H2 / Molar mass of C2H2
= 220 g / 26.04 g/mol
≈ 8.45 mol

Now that we have the number of moles of C2H2, we can use the stoichiometry of the balanced equation to determine the number of moles of CO2 produced.

Step 2: Calculate moles of CO2.
From the balanced equation, we know that 2 moles of C2H2 produce 4 moles of CO2.

Moles of CO2 = Moles of C2H2 * (4 moles CO2 / 2 moles C2H2)
= 8.45 mol * (4 mol CO2 / 2 mol C2H2)
= 16.9 mol

So, from 220 g of C2H2 and 545 g of O2, approximately 16.9 moles of CO2 could be produced.