The base of a right angled triangle is 12cm and its hypotenues is13 cm . Find the area of the triangle.
a^2 + 12^2 = 13^2
a^2 + 144 = 156
a^2 = 12
a = 3.46
A = (12 * 3.46)/2
Use the pythagorean theorem. x*x+12*12=13*13
x*x+144=169
x*x=25
x=5
5 is the side length of the remaining side.
to find the area of a right triangle you do base*height divided by two.
12*5=60
60/2=30
area=30
To find the area of a right-angled triangle, you can use the formula:
Area = (1/2) * base * height
Here, the base of the triangle is given as 12 cm. To find the height, you can use the Pythagorean theorem.
The Pythagorean theorem states that in a right-angled triangle, the sum of the squares of the two shorter sides (legs) is equal to the square of the longest side (hypotenuse). Mathematically, it can be written as:
a^2 + b^2 = c^2
Where a and b are the lengths of the legs, and c is the length of the hypotenuse.
In this case, you are given the base (12 cm) and the hypotenuse (13 cm). Let's call the height h.
Using the Pythagorean theorem, you can set up the equation:
12^2 + h^2 = 13^2
144 + h^2 = 169
Now, solve for h:
h^2 = 169 - 144
h^2 = 25
Taking the square root of both sides, you get:
h = √25
h = 5 cm
Now that you have the height (5 cm), you can substitute it into the formula for the area of a triangle:
Area = (1/2) * base * height
Area = (1/2) * 12 cm * 5 cm
Area = 60 square cm
Therefore, the area of the right-angled triangle is 60 square cm.