Abody moves along astraight line from A-B wiz uniform acceleration 2/3ms velocity at B is 25m/s.find velocity at A.find distance A-B.
I need the answer from u.thanx
The somewhat vague requirements give rise to the following equations of motion:
a = 2/3
v + (2/3)t = 25
vt + (1/3)t^2 = B-A
or
25t - 1/3 t^2 = B-A
Without knowing how long it took to get from A to B (only knowing that it is less than 75/2 seconds - why?), that's all we can do.
I need the answer from u.thanx
To find the velocity at point A, we need to use the equation of motion for uniformly accelerated motion:
v² = u² + 2as
where:
v = final velocity
u = initial velocity
a = acceleration
s = distance
Given:
acceleration (a) = 2/3 m/s²
final velocity at point B (v) = 25 m/s
Step 1: Find the initial velocity (u) at point A.
To find the initial velocity (u), we need to rearrange the equation of motion:
u² = v² - 2as
Substituting the given values:
u² = (25 m/s)² - 2 * (2/3 m/s²) * s
Step 2: Find the distance (s) from A to B.
To find the distance (s), we can use another equation of motion:
v = u + at
We need to rearrange this equation to solve for distance (s):
s = (v - u) / (2/3)
Substituting the values:
s = (25 m/s - u) / (2/3)
Step 3: Substitute the found value of initial velocity (u) into the equation from Step 1.
Substituting the value of u into the equation:
s = (25 m/s - √(25 m/s)² - 2 * (2/3 m/s²) * s) / (2/3)
Now, we have two equations with two variables (s and u).
By solving these two equations simultaneously, we can find the values of velocity at point A (u) and the distance from A to B (s).
Please provide any additional information or data given in the question to proceed with the calculations.