What is the equation of the line that passes through the points (−2, 1) and (1, 10)?
3x − y = −7
3x − y = −5
3x − y = 5
x + 3y = −5
the slope is 3, so the point-slope form is
y-1 = 3(x+2)
or
y-10 = 3(x-1)
Now just massage that into one of the choices.
idk how
y-1 = 3(x+2)
y-1 = 3x+6
y = 3x+7
-7 = 3x-y
3x-y = -7
Looks like (A) to me
To find the equation of a line that passes through two points, you can use the point-slope form of a linear equation. The point-slope form is given by y - y1 = m(x - x1), where (x1, y1) is one of the given points and m is the slope of the line.
1. First, find the slope of the line using the formula m = (y2 - y1) / (x2 - x1), where (x1, y1) and (x2, y2) are the coordinates of the two points.
Given points: (-2, 1) and (1, 10)
m = (10 - 1) / (1 - (-2))
m = 9 / 3
m = 3
2. Now that we have the slope, choose one of the points to substitute into the point-slope form. Let's use the point (-2, 1). Substitute the values into the equation:
y - y1 = m(x - x1)
y - 1 = 3(x - (-2))
y - 1 = 3(x + 2)
y - 1 = 3x + 6
3. Simplify the equation:
y = 3x + 6 + 1
y = 3x + 7
Therefore, the equation of the line that passes through the points (-2, 1) and (1, 10) is y = 3x + 7.