# Physics

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A ball is allowed to fall freely from certain heightn. What distance it covers in 1st second?

• Physics -

d = 0.5g*t^2 = 4.9*1^2 = 4.9 m.

• Physics -

As we know that
S=Vit+½at^2. a=g
OR
S=Vit+(0.5)gt^2
As Vi=0 then it becomes
S=(0.5)gt^2. g=9.8m/s..... (1)
Putting values in eq (1).
S=(0.5)(9.8)(1^2)
S=(0.5)(9.8) 0.5=½
OR
S=g/2
S=4.9m

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