An electric heater raises the temperature of 120g of water in a thin light vessel through 10K in 2mins, when placed in 70g of water contained in a metal vessel of mass 0.55kg the temperature rises through 9K in the same time. Calculate from the above:

a)the heat supplied in 2mins
b)the power of the heater
c)the heat supplied to the 70g of water
d)the heat supplied to the metal vessel
e)the heat capacity of the vessel
f) the specific heat capacity of its material (specific heat capacity of water = 4200)

I need solution

I need solution

I need solution

To solve this question, we can use the formula Q = mcΔT, where Q denotes the heat supplied, m represents the mass, c is the specific heat capacity, and ΔT is the change in temperature. Let's now calculate the answers to each part of the question.

a) The heat supplied in 2 minutes can be calculated for the first situation (120g of water) using the formula: Q = mcΔT = (120g)(4200 J/kg·K)(10 K) = 504,000 J.

b) To find the power of the heater, we can use the formula: Power = Q/t, where Q is the heat supplied (504,000 J) and t is the time (2 minutes = 120 seconds). Therefore, Power = 504,000 J / 120 s = 4200 W.

c) The heat supplied to the 70g of water can be found using the same formula: Q = mcΔT = (70g)(4200 J/kg·K)(9 K) = 2,646,000 J.

d) To determine the heat supplied to the metal vessel, we need to find the heat absorbed by the metal vessel. Since the temperature change is the same for both the water and the metal vessel, we can use the same formula: Q = mcΔT. The mass of the metal vessel is given as 0.55 kg. Let's assume the specific heat capacity of the metal vessel is x. Therefore, the heat supplied to the metal vessel is Q = (0.55 kg)(x J/kg·K)(9 K).

e) The heat capacity of the vessel is the heat required to raise its temperature by 1 K (degree). Since the change in temperature is the same for both water and the vessel, and we know the heat supplied to the water is 2,646,000 J, we can use the formula: heat capacity = Q / ΔT = 2,646,000 J / 9 K.

f) The specific heat capacity of the vessel's material can be found by dividing the heat capacity by the mass of the vessel: specific heat capacity = heat capacity / mass of the vessel = (2,646,000 J / 9 K) / 0.55 kg.

By substituting the given values into these formulas, you can calculate the values for each part of the question.