The sum of two numbers is 62, and their difference is 12. What are the numbers?
I need any help. Thank you
a+b = 62 so b = (62-a)
a - b = 12
a -(62-a) = 12
2 a - 62 = 12
2 a = 50
a = 25
b = 62-25 = 37
To find the two numbers, let's set up equations based on the given information.
Let's assume the two numbers are represented by variables x and y.
From the problem statement, we have two pieces of information:
1. The sum of the two numbers is 62: x + y = 62.
2. The difference between the two numbers is 12: x - y = 12.
We now have a system of equations. To solve for x and y, we can use several methods, such as substitution or elimination. Let's use the elimination method:
To eliminate one variable, we can add both equations:
(x + y) + (x - y) = 62 + 12
2x = 74
Now, let's solve for x by dividing both sides of the equation by 2:
2x/2 = 74/2
x = 37
Now that we have the value of x, we can substitute it back into one of the original equations to solve for y. Using x + y = 62:
37 + y = 62
y = 62 - 37
y = 25
Therefore, the two numbers are 37 and 25.
Thank you so much Damon, now I know how to do my other problems. Thanks :)
2 a - 62 = 12
2 a = 74 !!!!!
a = 37
b = 25
same answer anyway