Charlie had a board that was in the shape of a rectangle. The length was 2x-5 and the width was x-2. What is the perimeter of the rectangle?
P = 2L + 2W
P = 2(2x - 5) + 2(x - 2
P = 4x - 10 + 4x - 4
P = 8x - 14
Thank you so much Ms. Sue, you are a lifesaver:)
You're welcome, Stepfanie.
To find the perimeter of the rectangle, you need to add up the lengths of all four sides.
Given that the length of the rectangle is 2x-5 and the width is x-2, we can start by calculating the lengths of the sides.
The length is given as 2x-5, so there are two sides with that length. Therefore, the total length of these two sides is (2x-5) + (2x-5).
Similarly, the width is given as x-2, so there are two sides with that length. Thus, the total length of these two sides is (x-2) + (x-2).
Now, let's simplify the expressions:
(2x-5) + (2x-5) = 4x -10
(x-2) + (x-2) = 2x - 4
Finally, to find the perimeter, we add up the lengths of all four sides:
Perimeter = (4x - 10) + (2x - 4)
Combine like terms:
Perimeter = 4x + 2x - 10 - 4
Simplify further:
Perimeter = 6x - 14
Therefore, the expression 6x - 14 represents the perimeter of the rectangle.