calculus
posted by jake
find the maximum and minimum value of the function f(x)= xx^3 on the interval [2,2]
I also need help with this question
What is the largest possible product of two negative number whose sum is 1?

Damon
check end points
f(2) = 2+8 = 6
f(2) = 28 = 6
now find where derivative is zero
f' = 1 3x^2
= 0 when x = 1/sqrt3 or x = 1/sqrt3
if x = 1/sqrt 3
f = 1/sqrt3 1/3sqrt3 =(2/3sqrt3)
if x = 1/sqrt3
f = 1/sqrt3 +1/3sqrt 3
= (2/3sqrt3)
so the max and min are at the end points max at 2 and min at +2
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